๐ฐ Geometry Kingdom ยท Geometry
Volume & Surface Area
Compute volume and surface area of prisms, cylinders, pyramids, cones and spheres.
In short
- Volume fills a solid (cubic units); surface area covers it (square units).
- Box: V = lwh and S = 2(lw + lh + wh). Cube: V = s3 and S = 6s2.
- Cylinder: V = pi r2 h โ the base area times the height.
- Anything that tapers to a point takes a third: cone V = (1/3) pi r2 h, pyramid V = (1/3) B h.
- Sphere: V = (4/3) pi r3, with the radius cubed; a hemisphere is half of that, (2/3) pi r3.
- A cone uses the perpendicular height, never the slant height, and a diameter is halved before it enters any formula.
- 1 litre = 1000 cm3, and volumes are undone by dividing, since they are built by multiplying.
Filling versus wrapping
Two different questions can be asked about any solid.
Volume asks how much space it fills โ how many unit cubes fit inside. Three lengths are multiplied, so the units are cubic: cm3, m3.
Surface area asks how much material would cover the outside โ how much wrapping paper, paint or card. It is a sum of flat faces, so the units are square: cm2, m2.
Keeping the units in view is the fastest way to spot a mistake. A volume answered in cm2 is definitely wrong.
A useful mental image: volume is the water a tank holds; surface area is the metal the tank is made of.
Prisms and cubes
A rectangular prism (a box) with length l, width w and height h holds
V = l x w x h
Think of it as layers: the bottom layer holds l x w cubes, and there are h such layers stacked up.
Its surface is six rectangles in three matching pairs, so
S = 2(lw + lh + wh)
A cube is the special case where all three edges are equal:
V = s3 S = 6 s2
The 6 x (one face) shortcut works only for a cube. In a general box the three pairs of faces are different sizes, so all three products are needed.
Cylinders
A cylinder is a stack of identical circular discs. Its volume is therefore the area of the circular base times the height:
V = pi x r2 x h
For radius 3 and height 10 that is pi x 9 x 10 = 270*pi, or about 847.8 using pi = 3.14.
As with circles, the question will say whether it wants an exact answer in terms of pi or a decimal using pi = 3.14.
The commonest slips are doubling the radius instead of squaring it, and stopping after the base area without multiplying by the height.
The curved surface of a cylinder unrolls into a rectangle of width 2 pi r (the circumference) and height h, so the total surface area of a closed cylinder is 2 pi r2 + 2 pi r h.
Cones, pyramids and spheres
Three solids taper to a point or curve away, and each has its own factor in front.
A cone fills exactly one third of the cylinder standing on the same base circle with the same height:
V = (1/3) x pi x r2 x h
A pyramid does the same to its prism โ three identical pyramids fill the prism on the same base โ so with B for the area of the base,
V = (1/3) x B x h
For a square base of edge b that means B = b x b, and the volume is b x b x h / 3.
A sphere has no base to stand on, and its factor is four thirds:
V = (4/3) x pi x r3
The radius is cubed here, not squared. Half a sphere โ a hemisphere โ is half of that, which tidies to (2/3) x pi x r3.
Two warnings that catch nearly everyone. The h in a cone is the perpendicular height, measured straight up from the centre of the base to the tip; the slant height runs up the sloping side and belongs to surface area, never to volume. And a question that hands you a diameter is asking you to halve it first โ using it as the radius makes a cone or a sphere far too big.
Composite solids are just addition. A tank made of a cylinder with a hemispherical dome holds pi x r2 x h plus (2/3) x pi x r3: find each piece, then add.
Working backwards, and capacity
Because volume is built by multiplying, it is undone by dividing. If a tank has volume 480 cm3 and a base measuring 8 cm by 6 cm, then the base area is 48 cm2 and the depth is 480 / 48 = 10 cm.
Capacity is volume wearing different units. The key conversion is
1 litre = 1000 cm3
so a volume in cm3 is divided by 1000 to reach litres. Converting to a bigger unit always makes the number smaller, which is a good check: 4500 cm3 is 4.5 litres, not 4 500 000.
A related trap is scale. Doubling every edge of a box multiplies its surface area by 4 and its volume by 8 โ this is why large animals are shaped so differently from small ones.
Worked examples
Example 1
A box is 8 cm by 5 cm by 3 cm. Find its volume and its surface area.
- Volume: multiply all three edges, 8 x 5 x 3 = 120 cm3.
- For the surface, find one of each pair of faces: 8 x 5 = 40, 8 x 3 = 24, 5 x 3 = 15.
- Add them: 40 + 24 + 15 = 79.
- Each face has a twin, so S = 2 x 79 = 158 cm2.
Example 2
A cylinder has radius 5 cm and height 12 cm. Find its volume in terms of pi.
- Volume of a cylinder = pi x r2 x h.
- Square the radius: 52 = 25.
- Multiply by the height: 25 x 12 = 300.
- V = 300*pi cm3.
Example 3
A cone has radius 6 cm and perpendicular height 8 cm. Its slant height is 10 cm. Find its volume, using pi = 3.14 and rounding to 1 decimal place.
- Volume of a cone = (1/3) x pi x r2 x h. The slant height is not in that formula, so 10 cm is not used.
- Square the radius: 62 = 36.
- Base area = 3.14 x 36 = 113.04 cm2.
- Multiply by the height: 113.04 x 8 = 904.32.
- Take a third: 904.32 / 3 = 301.4 cm3 to 1 decimal place.
Example 4
A ball is a sphere of diameter 10 cm. Find its volume, using pi = 3.14 and rounding to 1 decimal place.
- The formula wants the radius, so halve the diameter first: r = 10 / 2 = 5 cm.
- Cube the radius: 53 = 5 x 5 x 5 = 125.
- V = (4/3) x pi x r3 = (4/3) x 3.14 x 125.
- 3.14 x 125 = 392.5, and four thirds of that is 392.5 x 4 / 3 = 523.3 cm3 to 1 decimal place.
Practice problems, with solutions
Three problems of increasing difficulty, each with the full working. In the game these are generated fresh every time; these three are fixed so this page always shows the same ones.
Problem 1
Difficulty 1 of 5A rectangular box measures 5 cm long, 3 cm wide and 5 cm high. Find its volume.
Answer: 75 cm3
- V = length x width x height
- V = 5 x 3 x 5
- V = 15 x 5 = 75 cm3
Problem 2
Difficulty 3 of 5A cube has edges of length 10 cm. Find its surface area.
Answer: 600 cm2
- Area of one face = 102 = 100 cm2
- A cube has 6 faces.
- S = 6 x 100 = 600 cm2
Problem 3
Difficulty 4 of 5A cylinder has radius 9 cm and height 19 cm. Find its volume. Use pi = 3.14 and round to 2 decimal places.
Answer: 4832.46 cm3
- V = pi x r2 x h
- r2 = 81
- V = 3.14 x 81 x 19
- V = 4832.46 cm3
Common mistakes
- Reporting a surface area when a volume was asked for, or using the wrong units.
- Counting only three faces of a box instead of six, or using the cube shortcut on a non-cube.
- Doubling the radius of a cylinder instead of squaring it, or forgetting to multiply by the height.
- Multiplying by 1000 when converting cm3 to litres instead of dividing.
- Leaving out the 1/3 for a cone or a pyramid, which gives the whole cylinder or prism instead.
- Treating a given diameter as the radius, so a cone comes out four times too big and a sphere eight times.
- Squaring the radius of a sphere instead of cubing it, or borrowing the 4/3 of a sphere for a cone.
- Putting the slant height of a cone into the volume formula in place of the perpendicular height.
What you should be able to do
- Find the volume of a prism and a cylinder.
- Find the surface area of a prism and a cylinder using nets.
- Apply the one-third factor for pyramids and cones.
- Use volume in capacity and packing word problems.
Where this fits in the curriculum
Common Core
Ontario
SAT
- Additional Topics in Math
Volume of prisms, cylinders, cones, pyramids and spheres.