🏰 Geometry Kingdom · Geometry

Similar Solids & Composite Figures

Scale the area and volume of similar figures by the square and cube of the scale factor, find the area of regular polygons, and measure composite figures and cross-sections of solids.

In short

  • If two similar solids have scale factor k, their lengths are in the ratio k, their areas in the ratio k2 and their volumes in the ratio k3 β€” one factor for each direction the shape grows in.
  • To go backwards, undo the power: a cube root turns a volume ratio into k, a square root turns an area ratio into k. To move between the area ratio and the volume ratio, always travel through k.
  • Every regular polygon has Area = (1/2) x apothem x perimeter, because the polygon splits into one triangle per side and each of those carries the half.
  • A composite figure is answered by splitting it into shapes you already know, then adding the pieces or subtracting the piece that was removed β€” and where two solids meet, both touching faces are hidden from a surface area.
  • Mass = density x volume, but how many boxes fit in a crate is not a volume division: round each direction down on its own and multiply the three counts.

Similar solids and the square-cube law

Two solids are similar when one is an exact enlargement of the other: same shape, every length multiplied by the same number. That number is the scale factor, written k. Surveyor Kit up at Polygon Peaks prices every job by it β€” perimeter is rope, area is paint, volume is stone to carry β€” and the three of them do not grow at the same rate.

Start with a cube of edge 1 and double it to edge 2.

  • Edges: 1 becomes 2. Multiplied by k = 2.
  • Faces: 1 by 1 becomes 2 by 2. Area is 1 becomes 4, multiplied by k2.
  • Whole solid: 1 by 1 by 1 becomes 2 by 2 by 2. Volume is 1 becomes 8, multiplied by k3.

An area is a length times a length, so it picks up the factor twice. A volume is a length times a length times a length, so it picks up the factor three times. That is the whole of the square-cube law, and it is why doubling a model does not double the stone.

Keep that little table in your head:

  • any length β€” an edge, a height, a radius, the perimeter β€” scales by k
  • any area β€” one face, or the whole surface area β€” scales by k2
  • any volume or capacity scales by k3

So if the scale factor is 2/3, the surface areas are in the ratio 4/9 and the volumes are in the ratio 8/27. A ratio question is answered as a fraction in lowest terms, exactly like 8/27, and the smaller solid always goes on top when the question says "smaller to larger".

You will also be asked to run this backwards. If two similar solids have volumes in the ratio 27/125, take the cube root of the top and the cube root of the bottom separately: k = 3/5. If their surface areas are in the ratio 9/49, take square roots: k = 3/7. And to get from one ratio to the other β€” areas 9/25 to volumes β€” there is no shortcut. Go back to k first (k = 3/5), then cube it (27/125).

Scaling a quantity, forwards and backwards

Once you have k, a number comes with it. If the smaller of two similar cones holds 40 cm3 and k = 3 from smaller to larger, the larger holds 40 x 33 = 40 x 27 = 1080 cm3. Going the other way you divide instead: the larger holds 1080, so the smaller holds 1080 / 27 = 40.

Two things make this go wrong, and both are easy to check.

  • Which power? Ask what the quantity is made of. Grams of paint cover a surface, so k2. Litres of water fill a space, so k3. A length of trim round an edge is just a length, so k.
  • Which direction? The larger solid must end up with the larger number. If your answer for the big one came out smaller than the number you started with, you divided when you should have multiplied.

The scale factor does not always arrive with a label on it. Often you get two matching lengths instead β€” "the heights are 4 cm and 6 cm" β€” and you build it yourself: k = 6/4 = 3/2 going up, and volumes then scale by (3/2)3 = 27/8. A fractional k is not a special case; it works the same way.

Modelling questions are the same idea in a bigger coat. "A model is built to a scale of 1 : 20" means every real length is 20 times the model's, so real capacity is 203 = 8000 times the model's. A model that holds 3 litres stands for a tank that holds 24000 litres. These questions often hand you a measurement you do not need β€” the model's height, say, when the capacity is already given. Extra information is not a hint; read what is asked and leave the spare number alone.

How to answer: a scaled quantity is exact. Type the whole number if it is one, or the single decimal place if it has one; the question tells you which to expect.

Regular polygons and the apothem

A regular polygon has all sides equal and all angles equal. Its apothem is the perpendicular distance from the centre to the middle of a side β€” not to a corner, which is longer.

Join the centre to every corner and a regular polygon with n sides falls apart into n identical triangles. Each triangle has base one side, s, and height the apothem, a, so each has area (1/2) x a x s. Add all n of them:

Area = n x (1/2) x a x s = (1/2) x a x (n x s)

and n x s is just the perimeter. So

Area = (1/2) x apothem x perimeter

One formula covers pentagons, hexagons, octagons and everything beyond. A hexagon of side 11 cm with apothem 9.5 cm has perimeter 6 x 11 = 66 cm and area (1/2) x 9.5 x 66 = 313.5 cm2.

Run it backwards and nothing new is needed. Given the area and the apothem, double the area, divide by the apothem to get the perimeter, then divide by the number of sides to get one side.

A regular hexagon is the one case where the apothem can be built from the side on its own: apothem = (side / 2) x sqrt(3). When a question asks for that, it will tell you to use sqrt(3) = 1.732, in the same spirit as pi = 3.14.

How to answer: areas here are rounded to 1 decimal place, and the prompt says so.

Composite figures: split, add, subtract

A composite figure is a shape built from pieces you already know. There is no formula for it and there does not need to be one. The method is always the same three steps: split it into familiar pieces, find each piece, then add or subtract.

  • A window that is a rectangle with a semicircle on top: rectangle plus half a circle.
  • A sign shaped like a house: rectangle plus triangle.
  • An L-shaped slab: the whole rectangle minus the corner that was cut out.
  • A square tile with a quarter circle cut away: square minus a quarter of a circle.
  • A hopper that is a cylinder with a cone on top, or a tank with a dome: the two volumes added.
  • A block with a slot cut out: the block minus the slot.

Three traps account for most lost marks. The first is the fraction of a circle: a semicircle is (1/2) x pi x r2, a quarter circle is (1/4) x pi x r2, a hemisphere is (2/3) x pi x r3 β€” half of the sphere's (4/3), not a third; the third belongs to cones. The second is the diameter wearing a radius costume: when a semicircle sits on a 12 cm edge, that 12 cm is the diameter and the radius is 6. The third is adding when you should subtract: cutting a piece away makes the figure smaller, so if your answer is bigger than the shape you started with, the sign is wrong.

Composite surface area has a trap of its own. Put a square pyramid on top of a cube and the cube's top face and the pyramid's base are pressed together, so neither of them is on the outside. Paint 5 squares and 4 triangles, not 6 and 5. Where two solids meet, both hidden faces drop out.

How to answer: anything with a circle in it says "use pi = 3.14" and asks for 1 decimal place; the checker also accepts the answer you get from the pi key on a calculator. Answers with no curve in them are whole numbers.

Cross-sections, density, and packing

Slice a solid with a flat plane and the flat face you expose is a cross-section. Picture the plane as a sheet of glass pushed through, and read the outline where it meets the surface.

The one rule worth memorising: a slice parallel to the base is a copy of the base, possibly smaller. So a cone or a cylinder sliced parallel to its base gives a circle; a square pyramid gives a square; a triangular prism sliced parallel to its triangular ends gives a triangle. Every other plane you have to picture on its own:

  • a cylinder cut straight down through the centre: a rectangle;
  • a cone cut straight down through its vertex: a triangle;
  • a square pyramid cut straight down through the apex: a triangle β€” but the same cut missing the apex leaves a trapezoid, because the sloping edges never meet;
  • a cone or cylinder cut at a slant: an ellipse, because the plane travels further one way than the other;
  • a sphere, cut any way at all: a circle.

Density ties measurement to the real world: density = mass / volume, so mass = density x volume. Iron at 7.8 grams per cubic centimetre means every single cubic centimetre carries 7.8 g, so find the volume first and multiply at the end. Population density is the same sentence about people: people per square kilometre, found by dividing the population by the area β€” and the area, not the distance round the outside.

Packing looks like density and is not. To ask how many 4 cm by 7 cm by 6 cm boxes fit inside a 19 cm by 16 cm by 15 cm crate, work along each direction separately and round down every time: 19 / 4 gives 4 boxes, 16 / 7 gives 2, 15 / 6 gives 2, so 4 x 2 x 2 = 16. Dividing the volumes would say 27, and 27 is wrong: it quietly assumes the leftover strips at the ends can be poured together into more boxes, and rigid boxes cannot be poured.

How to answer: a cross-section is a multiple choice β€” pick the shape's name. A mass, a population density and a box count are typed in, whole numbers or one decimal place as the question says.

Worked examples

Example 1

Two similar cones have surface areas in the ratio 16/49. What is the ratio of their volumes, smaller to larger?

  1. Surface areas scale by k2, so 16/49 is k2 and not k itself. Neither ratio turns into the other directly, so find k first.
  2. Take the square root of the top and of the bottom separately: sqrt(16) = 4 and sqrt(49) = 7, so k = 4/7.
  3. Volumes scale by k3, so cube the top and the bottom: 43 = 64 and 73 = 343.
  4. The ratio of the volumes is 64/343. It is already in lowest terms, and the smaller solid is on top, as the question asked.

Example 2

Two similar prisms have heights 6 cm and 10 cm. The smaller has volume 81 cm3. Find the volume of the larger.

  1. Build the scale factor from the two matching heights: k = 10/6, which cancels to 5/3 going from the smaller up to the larger.
  2. A volume scales by k3, so the volume factor is (5/3)3 = 125/27.
  3. The larger solid is bigger, so multiply: 81 x 125/27.
  4. 81 / 27 = 3, and 3 x 125 = 375. The larger prism has volume 375 cm3, which is sensibly bigger than 81.

Example 3

A window is a rectangle 8 cm wide and 10 cm tall with a semicircle resting on its 8 cm top edge. Find the total area. Use pi = 3.14 and round to 1 decimal place.

  1. Split the window into a rectangle and a half circle, and find them one at a time.
  2. Rectangle = 8 x 10 = 80 cm2.
  3. The 8 cm edge is the flat side of the semicircle, so it is the DIAMETER; the radius is 8 / 2 = 4 cm.
  4. Semicircle = (1/2) x 3.14 x 42 = (1/2) x 3.14 x 16 = 25.12 cm2.
  5. Total = 80 + 25.12 = 105.12, which is 105.1 cm2 to 1 decimal place.

Example 4

A regular octagon has area 172.8 cm2 and apothem 7.2 cm. How long is each side?

  1. Start from Area = (1/2) x apothem x perimeter and put in what you know: 172.8 = (1/2) x 7.2 x P.
  2. Undo the half by doubling both sides: 345.6 = 7.2 x P.
  3. Divide by the apothem: P = 345.6 / 7.2 = 48 cm. That is the perimeter, not the answer yet.
  4. An octagon has 8 equal sides, so each side is 48 / 8 = 6 cm.

Practice problems, with solutions

Three problems of increasing difficulty, each with the full working. In the game these are generated fresh every time; these three are fixed so this page always shows the same ones.

Problem 1

Difficulty 1 of 5

Two similar cones have slant heights of 6 cm and 9 cm. What is the ratio of their volumes, smaller to larger? Give the ratio as a fraction in lowest terms, for example 8/27.

Answer: 8/27

  1. k = 6/9 = 2/3
  2. Volumes are in the ratio k3 = (2/3)3
  3. = 8/27

Problem 2

Difficulty 3 of 5

Two similar square-based pyramids have base edges of 8 cm and 12 cm. The smaller one has volume 64 cm3. Find the volume of the larger one.

Answer: 216 cm3

  1. k = 12/8 = 3/2
  2. k3 = 27/8
  3. volume = 64 x 27/8 = 216 cm3

Problem 3

Difficulty 4 of 5

A regular octagon has area 946.4 cm2 and apothem 16.9 cm. How long is each side? Give your answer to 1 decimal place.

Answer: 14 cm

  1. A = (1/2) x apothem x perimeter, so 946.4 = (1/2) x 16.9 x P
  2. 2 x 946.4 = 16.9 x P, so P = 1892.8 / 16.9 = 112 cm
  3. A regular octagon has 8 equal sides.
  4. Side = 112 / 8 = 14 cm

Common mistakes

  • Scaling a volume by k instead of k3 (or an area by k instead of k2). Doubling every length of a tank makes it hold eight times as much, not twice as much.
  • Answering a ratio question with k when the volumes were asked for, or with the volumes when k was asked for. Read which of the three the question wants, then check the power you used matches it.
  • Writing the ratio upside down. "Smaller to larger" puts the smaller solid on top, and the fraction should come out less than 1.
  • Dropping the half in Area = (1/2) x apothem x perimeter, which doubles every polygon area, or using one side where the whole perimeter belongs.
  • Treating a diameter as a radius: when a semicircle sits on a 12 cm edge the radius is 6, not 12. Squaring the wrong one is a factor-of-four error.
  • Adding a piece that was cut away instead of subtracting it, so the answer comes out bigger than the shape it was cut from.
  • Counting a hemisphere as (1/3) of a sphere or as a whole one. A hemisphere is (2/3) x pi x r3; the (1/3) belongs to cones.
  • Dividing the crate volume by the box volume to count boxes. That answer is always too big, because it assumes the leftover strips at the ends can be merged.

What you should be able to do

  • Relate the scale factor of similar solids to the ratio of their surface areas and volumes.
  • Find the area of a regular polygon from its apothem and perimeter.
  • Find the area or volume of a composite figure by splitting it into known pieces.
  • Identify the cross-section of a solid and use density in a measurement problem.

Where this fits in the curriculum

Common Core

  • HSG-GMD.A.3

    High school β€” Use volume formulas for cylinders, pyramids, cones and spheres to solve problems.

  • HSG-GMD.B.4

    High school β€” Identify the shapes of two-dimensional cross-sections of three-dimensional objects.

  • HSG-MG.A.1

    High school β€” Use geometric shapes, their measures and their properties to describe objects.

  • HSG-MG.A.2

    High school β€” Apply concepts of density based on area and volume in modelling situations.

  • HSG-SRT.B.5

    High school β€” Use congruence and similarity criteria for triangles to solve problems and to prove relationships in geometric figures.

SAT

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