π Statistics Steppe Β· Statistics
The Normal Distribution
Use the bell curve to turn a value into a proportion and back: the empirical rule, z-scores with a table, percentiles, the value behind a percentage, and comparing scores from different distributions.
In short
- A normal distribution is a symmetric bell described by just two numbers: the mean at its centre and the standard deviation for its width.
- The empirical rule: about 68% within 1 standard deviation of the mean, 95% within 2, 99.7% within 3 β and symmetry halves each of those into 34%, 13.5% and 2.35% on one side.
- A z-score is a distance in standard deviations: z = (value - mean) / standard deviation. Going back is value = mean + z x standard deviation.
- A standard normal table gives the area to the LEFT of z. Above is 1 minus that, and the area left of a negative z is 1 minus the area left of its positive twin.
- The share between two values is the bigger table area minus the smaller one, never the two added together.
- A percentile is an area, not a z-score: the 90th percentile is the value with 90% of the data below it, and its z is 1.28.
- Raw scores from two different tests cannot be compared; their z-scores can, because a z-score has no units.
The bell, and the rule that comes with it
Surveyor Halden keeps every measurement the Tower has ever taken, and says the same shape keeps turning up. Measure the heights of a thousand reeds, the times of a thousand ferry crossings, the weights of a thousand grain sacks, and the picture is always a bell: a heap in the middle, thinning out evenly on both sides, with no second bump and no long tail on one side only.
A bell like that is called a normal distribution, and two numbers describe the whole of it:
- the mean, which sits under the peak β it is also the median, because the curve is symmetric;
- the standard deviation, which says how wide the heap is.
Because the shape is always the same, the share of the data in any band is always the same too, once you measure that band in standard deviations. That is the empirical rule, and it is worth knowing by heart:
about 68% within 1 standard deviation of the mean about 95% within 2 about 99.7% within 3
Symmetry then splits each band in half, and those halves are where most of the real questions live:
mean to 1 standard deviation above 34% (half of 68) 1 to 2 standard deviations above 13.5% (half of 95 - 68) 2 to 3 standard deviations above 2.35% above 2 standard deviations 2.5% (half of 100 - 95) below 1 standard deviation under 16% (half of 100 - 68)
So for reed heights with mean 70 cm and standard deviation 8 cm: about 68% of the reeds measure between 62 and 78 cm, about 34% between 70 and 78, about 2.5% above 86, and about 16% below 62. Everything there came from the mean, the standard deviation, and one memorised line.
The z-score, and the table it opens
The empirical rule only answers questions about whole numbers of standard deviations. For 74 cm, or 83 cm, you need the machinery underneath, and it starts with a z-score:
z = (value - mean) / standard deviation
A z-score is a distance measured in standard deviations. z = 1.4 means "1.4 standard deviations above the mean"; z = -0.8 means "0.8 standard deviations below it". A z-score has no units, which is exactly what makes it useful: it turns centimetres, minutes and points into one common ruler.
Once you have z, a standard normal table turns it into an area. Every question in this skill prints the rows it needs, so you never have to remember one. It looks like this:
z Area to the left of z 0.00 0.5000 0.50 0.6915 0.80 0.7881 1.00 0.8413 1.20 0.8849 1.30 0.9032 1.40 0.9192 1.50 0.9332 1.60 0.9452 1.80 0.9641 2.00 0.9772 2.50 0.9938
Read that column carefully: it is the area to the left of z, which is the proportion of the data BELOW that value. Areas are proportions between 0 and 1, so multiply by 100 to get a percent. 0.9192 is 91.92%, which rounds to 91.9%.
Two moves cover everything else.
Above instead of below. The whole curve is 1, so the area to the right is 1 minus the area to the left. If z = 1.4, then below is 0.9192 and above is 1 - 0.9192 = 0.0808, that is 8.1%.
A negative z. Tables print positive rows only, because the curve is symmetric and the negative half is a mirror of the positive half. The area to the left of -z equals 1 minus the area to the left of +z:
area left of -1.5 = 1 - 0.9332 = 0.0668, that is 6.7%
Sketch the bell and shade the region before you look anything up. One shaded picture prevents almost every error in this topic.
Between two values, and outside them
A question that names two values is really two look-ups. Both table entries measure from the far left, so the strip between them is the bigger area minus the smaller one β never the sum.
P(a < X < b) = (area left of z for b) - (area left of z for a)
Take grain sack weights with mean 70 kg and standard deviation 10 kg, and ask what share weighs between 78 and 84 kg.
z for 78 = (78 - 70) / 10 = 0.8 -> 0.7881 z for 84 = (84 - 70) / 10 = 1.4 -> 0.9192 between = 0.9192 - 0.7881 = 0.1311, that is 13.1%
If the strip straddles the mean, one z is negative and you use symmetry on that one first. Between 55 and 84, with the same sacks:
z for 55 = -1.5 -> 1 - 0.9332 = 0.0668 z for 84 = 1.4 -> 0.9192 between = 0.9192 - 0.0668 = 0.8524, that is 85.2%
Notice the sense check: a strip that covers most of the middle of the bell ought to come out large, and 85.2% is large. A strip out in a tail ought to come out small. If your arithmetic disagrees with your sketch, trust the sketch and hunt for the slip.
Outside a range is the leftover: work out what lies between, then subtract from 100%. That is exactly how a tolerance question at the forge works. Bolts with mean length 10 mm and standard deviation 0.1 mm, sent back if they fall outside 9.8 to 10.2 mm, are being measured against limits 2 standard deviations either side of the mean β 95% inside, so about 5% go back.
To turn a percent into a count, multiply by the size of the batch and round only at the very end:
0.8524 x 500 = 426.2, so about 426 sacks
Percentiles, cut-offs, and two different tests
A percentile is an area wearing a different hat. Being at the 90th percentile means 90% of the data lies below you. So percentile questions run in whichever direction you are missing a piece.
Value to percentile. Find z, look up the area, multiply by 100. A reed of 78 cm among reeds with mean 70 and standard deviation 8 has z = 1, an area of 0.8413, and so sits at about the 84th percentile.
Percentile to value. Go the other way: find the area in the table, read the z beside it, then undo the z-score.
value = mean + z x standard deviation
For the 90th percentile, hunt for 0.9000 in the area column. It falls between the rows for 1.20 and 1.30, and the standard value used for it is z = 1.28 β where a question needs one of these in-between numbers, it tells you which z to use. With mean 70 and standard deviation 10:
value = 70 + 1.28 x 10 = 82.8
A cut-off is the same calculation in costume. "The top 10% are pinned to the survey board" means 90% lie below the cut-off, so the cut-off is the 90th percentile, 82.8. "The bottom 5% measure again" means z = -1.645, and the cut-off is 70 - 16.45 = 53.6. Watch the direction: a top slice sits above the mean and a bottom slice below it.
Two different tests. Raw scores from different distributions cannot be compared, because each test has its own mean and its own spread. z-scores can, because they are all on the same ruler.
Ines scored 82 where the mean was 70 and the standard deviation 8. Kofi scored 63 where the mean was 55 and the standard deviation 4.
Ines: z = (82 - 70) / 8 = 1.5 Kofi: z = (63 - 55) / 4 = 2.0
Kofi's raw score is nineteen points lower and his result is the stronger one: he stood 2 standard deviations above his own crowd, and Ines stood 1.5 above hers. Ranking three readings works the same way β convert all three, then order the z-scores, remembering that a negative z is below the average of that test.
How to type your answer
Halden marks answers by what was asked for, so read the last line of the prompt before you type.
A proportion is a percent to 1 decimal place. Give 8.1, not 0.0808 and not "8.08%". The percent sign is optional β 8.1 and 8.1% are both accepted β but the rounding is not, so carry the four decimal places of the table right to the end and round once.
0.9192 -> 91.9 0.0808 -> 8.1 0.1311 -> 13.1
The empirical-rule answers are typed the same way: 68, 95, 99.7, 34, 13.5, 16, 2.5, 5.
A count is a whole number. "About how many of 500 sacks" wants 426, not 85.2 and not 426.2. Multiply first, round last.
A value is a whole number or a decimal, exactly as the prompt says. A percentile read straight off the table lands on a whole number of centimetres; a cut-off built from z = 1.28 or z = 1.645 is asked for to 1 decimal place.
An interval is a pair, smaller number first. The middle 95% of reeds with mean 70 and standard deviation 8 is typed as
(54, 86)
A comparison is a choice. Pick the option β the name of the person who did better, or the ranking β rather than typing a z-score. The z-scores are your working, not your answer.
Every question that goes beyond the 68-95-99.7 rule prints the table rows it needs right beside the prompt. There is nothing to memorise except the formula for z, the fact that the table gives the area to the left, and the symmetry step for a negative z.
Worked examples
Example 1
Ferry crossing times are approximately normal with mean 24 minutes and standard deviation 3 minutes. About what percent of crossings take between 27 and 30 minutes? A tally covers 400 crossings; about how many of them is that?
- Measure the two ends in standard deviations. 27 is (27 - 24) / 3 = 1 standard deviation above the mean, and 30 is (30 - 24) / 3 = 2 above.
- So the region asked for is the slice between 1 and 2 standard deviations above the mean.
- The empirical rule gives 95% within 2 standard deviations and 68% within 1, so the two slices between them hold 95 - 68 = 27% of the data.
- That 27% is shared by the slice above the mean and its mirror below, so one slice holds 27 / 2 = 13.5%.
- For the count: 13.5% of 400 = 0.135 x 400 = 54 crossings.
- Answers: 13.5 as a percent, and 54 as a count.
Example 2
Reed heights are approximately normal with mean 70 cm and standard deviation 10 cm. Using the table, what percent of the reeds are taller than 84 cm?
- Convert the value to a z-score: z = (84 - 70) / 10 = 1.4.
- Look up the row z = 1.40. The area to the left of it is 0.9192, so 91.92% of the reeds are SHORTER than 84 cm.
- The question asked for taller, which is the other side of the curve: 1 - 0.9192 = 0.0808.
- As a percent that is 8.08%, which rounds to 8.1%.
- Sense check: 84 is well above the mean, so only a small share should be beyond it. 8.1% is suitably small.
Example 3
Grain sack weights are approximately normal with mean 70 kg and standard deviation 10 kg. What percent of the sacks weigh between 55 and 84 kg?
- Two values means two z-scores. z for 55 is (55 - 70) / 10 = -1.5, and z for 84 is (84 - 70) / 10 = 1.4.
- The table prints positive rows only. For z = 1.4 read 0.9192 straight off.
- For z = -1.5, use symmetry: the area to the left of -1.5 is 1 - 0.9332 = 0.0668.
- Both areas are measured from the far left, so subtract to get the strip between them: 0.9192 - 0.0668 = 0.8524.
- As a percent that is 85.24%, which rounds to 85.2%. The strip covers most of the middle of the bell, so a large answer is what the sketch predicts.
Example 4
Apprentice survey scores are approximately normal with mean 120 points and standard deviation 15 points. Halden pins the top 10% to the survey board. Use z = 1.28 for the 90th percentile and find the lowest score that makes the board, to 1 decimal place.
- The top 10% leaves 90% below the cut-off, so the cut-off is the 90th percentile.
- The 90th percentile is z = 1.28: the cut-off sits 1.28 standard deviations above the mean.
- Undo the z-score: value = mean + z x standard deviation = 120 + 1.28 x 15.
- 1.28 x 15 = 19.2 points.
- value = 120 + 19.2 = 139.2 points, to 1 decimal place.
- Check the direction: a top slice must sit above the mean, and 139.2 is above 120.
Practice problems, with solutions
Three problems of increasing difficulty, each with the full working. In the game these are generated fresh every time; these three are fixed so this page always shows the same ones.
Problem 1
Difficulty 1 of 5On the survey board this season, the lantern burn times are approximately normal with mean 30 hours and standard deviation 5 hours. About what percent of the lanterns have a burn time between 15 and 45 hours? Give your answer as a percent to 1 decimal place.
Answer: 99.7 %
- 15 and 45 sit 3 standard deviations either side of 30.
- The empirical rule gives about 99.7% for that region.
- So about 99.7% of the lanterns have a burn time between 15 and 45 hours.
Problem 2
Difficulty 3 of 5From the top of the Survey Tower, the apprentice survey scores are approximately normal with mean 28 points and standard deviation 4 points. The middle 95% of the apprentice survey scores lie between which two values, in points? Give the pair smaller value first, as (smaller, larger).
Answer: (20, 36)
- 95% is the band within 2 standard deviations of the mean.
- 2 x 4 = 8 points.
- Lower end: 28 - 8 = 20. Upper end: 28 + 8 = 36.
- The middle 95% runs from 20 to 36 points, typed as (20, 36).
Problem 3
Difficulty 4 of 5At the Survey Tower, the apprentice survey scores are approximately normal with mean 150 points and standard deviation 25 points. What percent of the apprentices have a survey score above 105 points? Use the standard normal table shown, and give your answer as a percent to 1 decimal place.
Answer: 96.4 %
- z = (105 - 150) / 25 = -1.8.
- Table row z = 1.80: area to the left = 0.9641.
- By symmetry, the area to the left of -1.8 is 1 - 0.9641 = 0.0359.
- Above: 1 - 0.0359 = 0.9641, which is 96.4%.
Common mistakes
- Giving the area to the left when the question asked what lies above. The table always hands you the left; if the prompt says "above", "more than" or "the top", subtract from 100%.
- Forgetting the symmetric half β answering 68% for the region from the mean up to 1 standard deviation, when that region is only half of the band, 34%. The same slip turns 5% into an answer where 2.5% was wanted.
- Swapping the mean and the standard deviation in the z formula. It is (value - mean) divided by the standard deviation, always in that order, and the subtraction comes first.
- Reading a percentile as if it were a z-score, and working out mean + 0.90 x standard deviation for the 90th percentile. The percentile is an area; the table turns it into z = 1.28 first.
- Adding the two table areas for a "between" question. Both are measured from the far left, so the strip between them is a subtraction.
- Rounding too early: rounding the proportion to a whole percent and then multiplying by the batch size, instead of carrying all four decimal places and rounding the count at the very end.
- Comparing two raw scores from tests with different means and spreads. The higher raw score is often the weaker result once both are turned into z-scores.
What you should be able to do
- Use the empirical rule to find the proportion of a normal distribution within or beyond 1, 2 or 3 standard deviations.
- Convert a value to a z-score and use a table to find the proportion below, above or between values.
- Find the value that sits at a given percentile.
- Compare two values from different normal distributions using z-scores.
Where this fits in the curriculum
Common Core
- HSS-ID.A.4
High school β Use the mean and standard deviation of a data set to fit it to a normal distribution and to estimate population percentages; recognise that there are data sets for which such a procedure is not appropriate; use calculators, spreadsheets and tables to estimate areas under the normal curve.
- HSS-ID.A.2
High school β Use statistics appropriate to the shape of the data distribution to compare centre and spread of two or more different data sets.
SAT
- Problem Solving and Data Analysis
Proportions of a normal distribution from the mean and standard deviation.